\(n_{Cu}=\dfrac{6,4}{64}=0,1\left(mol\right)\\
pthh:2Cu+O_2\underrightarrow{t^o}2CuO\)
0,1 0,1
\(V_{KK}=\left(0,1.22,4\right):20\%=11,2l\\
pthh:2KClO_3\xrightarrow[xtMnO_2]{t^o}2KCl+3O_2\)
\(\dfrac{1}{15}\) 0,1
\(m_{KClO_3}=\dfrac{1}{15}.122,5=\dfrac{49}{6}g\)