\(m_C=74,07\%.162=120\left(đvC\right)\Rightarrow n_C=\dfrac{120}{12}=10\left(mol\right)\)
\(m_H=8,65\%.162=14\left(đvC\right)\Rightarrow n_H=\dfrac{14}{1}=14\left(mol\right)\)
\(m_N=162-120-14=28\left(đvC\right)\Rightarrow n_N=\dfrac{28}{14}=2\left(mol\right)\)
⇒ CTHH của nicotin là C10H14N2