Hình như trên
S ABC là: 15 x 10 : 2 = 75 ( cm2 )
S ABM = SAMC
S IBM = S IMC
=> S AIB = S AIC
S ABI = S IBC x 2
=> S AIB là 1 phần và S AIC là 1 phần và S IBC là 0.5 phần
S AIC là:
75 : ( 1 + 1 + 0.5 ) x 1 = 30 ( cm2 )
S IDC = 1/3 S AIC = 30 x 1/ 3 = 10 cm2
S IMC = 1 / 2 S IBC = 15x1/2 = 7.5 cm2
S IMCD = 10 + 7.5 = 17.5 cm2
tại sao diện tích AIB=IBCx2 và tại sao S AIB và S AMC=1 phần mà trong khi đó IBC chỉ có 0.5 phần
mik đang cần bài này , thank you bạn rất nhìu
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Diện tích tam giác ABC là: 10 x 15 : 2 = 75 (cm2)
Vì M là trung điểm BC, suy ra:
SABM = SACM
SBIM = SCIM
Suy ra: SABI = SACI
Vì DC = 1/3 AC, suy ra: AD = 2 x CD
Suy ra:
SABD = 2/3 x SABC (chung đường cao hạ từ B và có DC = 1/3 AC)
SABD = 2/3 x 75 = 50 (cm2)
SBCD = 1/3 x SABC (chung đường cao hạ từ B và có DC = 1/3 AC)
SBCD = 1/3 x 75 = 25 (cm2)
SCDI = 1/3 x SACI (chung đường cao hạ từ I và có AD = 2 x CD)
Vì SABI = SACI và SCDI = 1/3 x SACI. Suy ra: Tỉ số giữa SCDI và SABD là 1/5
Mà SABD = 50 (cm2). Suy ra: SCDI = 50 : 5 = 10 (cm2)
Vì SBIM = SCIM, SBCD = 25 (cm2) và SCDI = 10 (cm2). Suy ra: SCIM = (25 - 10) : 2 = 7,5 (cm2)
Suy ra: SIMCD = SABD + SCIM = 10 + 7,5 = 17,5 (cm2)
những cách giải này sao khó hiểu quá. ai làm được thì giải rõ giúp mk nhé. à ai có nhu cầu thì kb với mk nhà,mk mới tham gia nên ko biết nhiều . thanks you very much
Hà Anh Thư ơi Thank ko có s nhae bạn
này Trần Thanh Xuân tại sao S ABI=S IBC vậy