Đổi 100ml=0,1l
\(Al+2HCl\rightarrow AlCl_2+H_2\)
tl1........2.............1..........1.(mol)
Br0,15...0,3......0,15.....0,15(mol)
\(n_{HCl}=C_M.Vdd=0,1.3=0,3\left(mol\right)\)
\(m_{Al}=n.M=0,15.27=4,05\left(g\right)\)
\(V_{H_2}=n.22,4=3,36\left(l\right)\)