Câu 4:
\(n_{CO_2}=\dfrac{m}{M}=\dfrac{17,6}{44}=0,4\left(mol\right)\\ \Rightarrow V_{CO_2}=n.22,4=0,4.22,4=8,96\left(l\right)\)
Câu 5:
\(n_{CH_4}=\dfrac{V}{22,4}=\dfrac{8,96}{22,4}=0,4\left(mol\right)\\ \Rightarrow m_{O_2}=m_{CH_4}=n.M=0,4.16=6,4\left(g\right)\\ \Rightarrow n_{O_2}=\dfrac{m}{M}=\dfrac{6,4}{32}=0,2\left(mol\right)\\ \Rightarrow V_{O_2}=n.22,4=0,2.22,4=4,48\left(l\right)\)