Question

Câu 23 nha

Answer 1

tình hình là k thấy câu 23?

Answer 2

\(n_{Cu}=\dfrac{12,8}{64}=0,2\left(mol\right)\)

PTHH: Cu + 2H₂SO_{4(đặc, nóng)} ---> CuSO₄ + SO₂↑ + 2H₂O

          0,2-------------------------------------------->0,2

Gọi \(\left\{{}\begin{matrix}n_{Na_2SO_3}=a\left(mol\right)\\n_{NaHSO_3}=b\left(mol\right)\end{matrix}\right.\)

PTHH:

SO₂ + 2NaOH ---> Na₂SO₃ + H₂O

a<-------2a<-------------a

SO₂ + NaOH ---> NaHSO₃

b<-------b<-----------b

=> \(\left\{{}\begin{matrix}a+b=0,2\\126a+104b=23\end{matrix}\right.\Leftrightarrow a=b=0,1\left(mol\right)\)

=> \(V_{ddNaOH}=\dfrac{0,1+0,1.2}{2}=0,15\left(l\right)\)