Question

câu 2: giải pt \(\sqrt{\left(2x+3\right)^2}=5\)

Answer 1

\(\sqrt{\left(2x+3\right)^2}=5\)

\(\Leftrightarrow2x+3=5\)

\(\Leftrightarrow2x=5-3\)

\(\Leftrightarrow2x=2\)

\(\Leftrightarrow x=1\)

Answer 2

\(\sqrt{\left(2x+3\right)^2}=5\)

\(\Leftrightarrow\left|2x+3\right|=5\)

\(\Leftrightarrow\left[{}\begin{matrix}2x+3=5\\2x+3=-5\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-4\end{matrix}\right.\)