Question

Câu 17: Tìm $x$ sao cho $\dfrac{x+2022}{\sqrt{25}}-\dfrac{x+|-2022|}{3}=\dfrac{x}{2}+1011$.

Answer 1

  

Answer 2

25​x+2022​−3x+∣−2022∣​=2x​+1011

�+20225−�+20223−�+20222=05x+2022​−3x+2022​−2x+2022​=0

(15−13−12)(�+2022)=0(51​−31​−21​)(x+2022)=0

$(x+2022)=0$

Answer 3

25​x+2022​−3x+∣−2022∣​=2x​+1011

�+20225−�+20223−�+20222=05x+2022​−3x+2022​−2x+2022​=0

(51​−31​−21​)(x+2022)=0

(x+2022)=0

x=-2022

 

Answer 4

tao đéo biết

Answer 5

x = -2022.

Answer 6

(x + 2022)/5 - (x + 2022)/3  = x/2 + 1011

(x + 2022) . (1/5 - 1/3) = x/2 + 1011

(x + 2022) . (-2/15) = x/2 + 1011

(x + 2022) . ( -4/15) = x + 2022

(x + 2022) (-4/15 - 1) = 0

(x + 2022) = 0

x = -2022