Bài 1:
a: Sửa đề 3n+4 chia hết cho n-3
\(\Leftrightarrow3n-9+13⋮n-3\)
\(\Leftrightarrow n-3\in\left\{1;-1;13;-13\right\}\)
hay \(n\in\left\{4;2;16;-10\right\}\)
b: ta có: \(n^2+2n+11⋮n+2\)
\(\Leftrightarrow n\left(n+2\right)+11⋮n+2\)
\(\Leftrightarrow n+2\in\left\{1;-1;11;-11\right\}\)
hay \(n\in\left\{-1;-3;9;-13\right\}\)