a/
\(\Leftrightarrow\frac{\sqrt{3}}{2}cos20x+\frac{1}{2}sin20x=cos21x\)
\(\Leftrightarrow cos\left(20x-\frac{\pi}{6}\right)=cos\left(21x\right)\)
\(\Leftrightarrow...\)
b/
Nhận thấy \(cosx=0\) ko phải nghiệm, chia 2 vế cho \(cos^2x\)
\(\Leftrightarrow2tan^2x-4tanx+4=1+tan^2x\)
\(\Leftrightarrow tan^2x-4tanx+3=0\)
\(\Leftrightarrow\left[{}\begin{matrix}tanx=1\\tanx=3\end{matrix}\right.\)
\(\Leftrightarrow...\)