a) \(\dfrac{-4}{7}x+\dfrac{1}{3}=\dfrac{7}{3}\)
\(\dfrac{-4}{7}x=\dfrac{7}{3}-\dfrac{1}{3}\)
\(\dfrac{-4}{7}x=2\)
\(x=2\div\dfrac{-4}{7}\)
\(x=\dfrac{-7}{2}\)
Vậy \(x=\dfrac{-7}{2}\)
b) \(x+80\%x=-1\dfrac{2}{5}\)
\(1x+\dfrac{4}{5}x=\dfrac{-7}{5}\)
\(\left(1+\dfrac{4}{5}\right)x=\dfrac{-7}{5}\)
\(\dfrac{9}{5}x=\dfrac{-7}{5}\)
\(x=\dfrac{-7}{5}\div\dfrac{9}{5}\)
\(x=\dfrac{-7}{9}\)
Vậy \(x=\dfrac{-7}{9}\)
a) −47x+13=73−47x+13=73
−47x=73−13−47x=73−13
−47x=2−47x=2
x=2÷−47x=2÷−47
x=−72x=−72
Vậy x=−72x=−72
b) x+80%x=−125x+80%x=−125
1x+45x=−75