Question

Cân Bằng Hai PTHH sau: 

1. CnH2n - 6 + O2 → CO2 + H2O 

2. CnH2n + 2O + O2 → CO2 + H2O 

Answer 1

\(C_nH_{2n-6}+\dfrac{3n-3}{2}O_2\underrightarrow{^{^{t^0}}}nCO_2+\left(n-3\right)H_2O\)

\(C_nH_{2n+2}O+\dfrac{3n}{2}O_2\underrightarrow{^{^{t^0}}}nCO_2+\left(n+1\right)H_2O\)

 

Answer 2

$1) C_nH_{2n-6} + \dfrac{3n-3}{2}O_2 \xrightarrow{t^o} n CO_2 + (n - 3) H_2O$

$2) C_nH_{2n+2}O + \dfrac{3n}{2}O_2 \xrightarrow{t^o} nCO_2 + (n + 1)H_2O$

Answer 3

CnH2n-6 +\(\dfrac{3n-3}{2}\)O2 -> nCO2 + (n-3)H2O

CnH2n+2O + \(\dfrac{3n}{2}\)O2 -> nCO2 + (n+1)H2O

Answer 4

 

nha bạn ới

Answer 5

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Answer 6

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