Question

Các cậu ơi giúp mk!!! Mai mk nộp bài rồi!!!😭😭😭

Bài tập:

Tìm x, biết:​

a) 2018 x—1 + 2019x (1–2018x)=0

b) ( x+2)³ — x² (x—6)= 4

____ HELP!!!!!!____

 

 

 

Answer 1

đặt ẩn phụ là ra

tích cho t đi

Answer 2

a) (2018x - 1) - 2019x (2018x - 1)=0

<=> (2018x - 1)(1 - 2019x)=0

<=> 2018x-1=0

1-2019x=0

<=> x=1/2018

x=1/2019

Answer 3

b) x^3 + 6x^2 + 12x + 8 - x^3 + 6x^2 - 4=0

<=> 12x^2 + 12x + 4=0

<=> 12x^2 + 6x + 8x + 4=0

<=> 6x(2x + 1) + 4(2x+1)=0

<=> 2(3x+2)(2x+1)=0

<=> 3x+2=0

2x+1=0

<=> x=-2/3

x=-1/2

Answer 4

a) \(2018x-1+2019x\left(1-2018x\right)=0\)

   \(2018x-1-2019x\left(2018x-1\right)=0\)

   \(\left(2018x-1\right)\left(1-2019x\right)=0\)

   \(\Rightarrow\orbr{\begin{cases}2018x-1=0\\1-2019x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2018}\\x=\frac{1}{2019}\end{cases}}}\)