Ta có : P (2019 ) = 2019a+b
P (1) = a+b
Khi đó , ta có : | P(2019) - P(1) | = | (2019a+b ) - (a+b ) |
= | ( 2019a+b -a-b |
= | 2018a |
Vì \(a\ne0\Rightarrow\left|2018a\right|\ne0\Rightarrow2018a\ge2018\)
Cho biet x=-2 la nghiem cua da thuc P(x) = ax+b (a khac 0)
Tinh gia tri cua bieu thuc \(\frac{2011a+b}{3a-b}\)
Xin loi cac ban vi may minh bi hong nen khong viet dau duoc. Mong cac ban giup do minh nhe!
Tim x, y, z biet
a ) |x-3,5|+ |x+5|=0
b) |x-1| + (y+1)^2 + |z-1|=0
c) ( x-1/3)^2 + (y-2)^2+ (z-1)^2 be hon hoac bang 0
d)(x-z)^2+ (y+x)^2 + (z+1/4)^2 =0
Cac ban giup minh voi minh can gap lam
cho cac da thuc f(x)=ax+b va g(x)=bx+a trong do a;b khac 0 biet rang nghiem cua da thuc f(x) la so duong cmr nghiem cua da thuc g(x) cung la 1 so duong
cho don thuc 3(a+1/a)x^4y^2 voi a la hang so ,a khac 0
a)tim a de da thuc luon khong am voi moi x,y
b)tim a de da thuc luon khong duong voi moi x,y
cho da thuc f(x)=ax^2+bx+c voi a,b,c la cac so thuc . Biet rang f(0), f(1), f(2) co gia tri nguyen . cmr : 2a, 2b cung co gt nguyen
chof(x)=ax^2+bx+cvoi a b c là các số hữu tỉ thỏa mãn 13a+b+2c=0 cmr f(-2)xf(3),nho hon bang 0
Cho da thuc f(x)=ax+b. Biet f(-2)=0 va f(2)=8. Tim a va b
mong cac ban giup do <3
Cho hai da thuc P(x) bang x4 cong ax2 cong 1 va Q(x) bang x3 cong ax cong 1 . Hay xac dinh a de hai da thuc tren co nghiem chung Mong cac ban thong cam may mk ko an dc dau
cho ham so y= f(x) =6/x
tinh f(1) ; f(1.5) ;f(2) ;f(3) ;f(-2/3)
tim x biet y=3 ; y=-2
tim y biet 1<x>3 ; 1.5 be hon hoac bang x lon hon hoac bang 6
diem nao trong cac diem sau day khong thuoc do thi ham s
A(-1;-6 ) ; B(-0.5 ;-12 ) ;C(-0.5 ; -13 ) ; D(-1/3 ; -3 )
Cac ban oi giup minh voi
tim x biet 6.4/x=x/99tim cac so nguyen biet (|x|-3)(x^2+4) be hon hoac bang 4hai dia diem a va b cach nhau 90kmhai nguoi di xe dap cung mot luc tu ava bde gap nhau va ho gap nhau cach a 50km;nhung neu nguoi di tu b di nhanh hon xuat phat truoc nguoi a 1 gio thi ho gap nhau cach a 350/9km tinh van toc moi nguoiCac giai ho minh voi minh se tick cho
Cac ban nho viet ho cach lam min voi
