Question

các bạn giúp mình với:

Tính :a) 2x²-5xy+3y²+4x²+xy-2y²

^{b) 2x^2 - 5xy+3y^2+4x^2+xy-2y^2+2x^2+4xy-5y^2}

 

Answer 1

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Answer 2

a)\(\left(2x^2+4x^2\right)+\left[\left(-5xy\right)+xy\right]+\left(3y^2-2y^2\right)=6x^2-4xy+y^2\)

b)\(2x^2-5xy+3y^2+4x^2+xy-2y^2+2x^2+4xy-5y^2\)

=\(\left(2x^2+4x^2+2x^2\right)+\left(-5xy+xy+4xy\right)+\left(3y^2-2y^2-5y^2\right)\)

=\(8x^2-4y^2\)

Answer 3

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Answer 4

a)2x²-5xy+3y²+4x²+xy-2y²

=\(\left(2x^2+4x^2\right)+\left(-5xy+xy\right)+\left(3y^2-2y^2\right)\)

\(=6x^2-4xy+y^2\)

b)2x² - 5xy+3y²+4x²+xy-2y²+2x²+4xy-5y²

\(=\left(2x^2+4x^2+2x^2\right)+\left(3y^2-2y^2-5y^2\right)+\left(5xy+xy+4xy\right)\)

\(=8x^2-4y^2+10xy\)