\(2x+12=3\left(x-7\right)\)
\(\Leftrightarrow2x+12=3x-21\)
\(\Leftrightarrow2x-3x=-12-21\)
\(\Leftrightarrow-x=-33\)
\(\Leftrightarrow x=33\)
bỏ dấu\(\Leftrightarrow\)cx đc nhé,lp 6 chx hok đến phương trình
#hoktot<3#
\(2x+12=3\left(x-7\right)\)
\(\Leftrightarrow2x+12=3x-21\)
\(\Leftrightarrow2x+12-3x+21=0\)
\(\Leftrightarrow-x+33=0\Leftrightarrow33-x=0\Leftrightarrow x=33\)
\(2x+12=3\left(x-7\right)\)
=> \(2x+12=3x-21\)
=> \(3x-2x=12+21\)
=> \(x=33\)
2x + 12 =3.(x - 7)
=>2x + 12 =3x - 21
=>3x-2x=21+12
=>x=33