Question

caanf gấp giúp mik với

Answer 1

\(3.1\\ a,\left(\dfrac{3}{5}+x\right)=\dfrac{3}{35}-\dfrac{2}{7}\\ \dfrac{3}{5}+x=\dfrac{3-2.5}{35}\\ \dfrac{3}{5}+x=-\dfrac{1}{5}\\ x=-\dfrac{1}{5}-\dfrac{3}{5}\\ x=\dfrac{-4}{5}\\ b,5x=0hoac2x-\dfrac{1}{3}=0\)

+, 5x = 0

x=0

+, \(2x-\dfrac{1}{3}=0\\ 2x=\dfrac{1}{3}\\ x=\dfrac{1}{3}:2\\ x=\dfrac{1}{6}\)

\(c,\left(6+2x\right)\left(x-1\right)=0\\ 6+2x=0hoacx-1=0\)

+, x - 1 =0

x= 1

+, \(6+2x=0\\ 2x=-6\\ x=-3\)