\(a,\dfrac{2}{3}x=\dfrac{7}{10}+\dfrac{1}{5}\\ \dfrac{2}{3}x=\dfrac{7+2}{10}\\ \dfrac{2}{3}x=\dfrac{9}{10}\\ x=\dfrac{9}{10}:\dfrac{2}{3}\\ x=\dfrac{27}{10}\\ b,x:2,5=1,5.\left(3+1\right)\\ x:2,5=1,5.4\\ x:2,5=6\\ x=6\times2,5\\ x=15\)
Tìm x, biết:
a) \(\dfrac{-1}{10}\) + \(\dfrac{2}{5}\)x + \(\dfrac{7}{20}\) = \(\dfrac{1}{10}\)
b) \(\dfrac{1}{3}\) + \(\dfrac{1}{2}\) : x= \(-\dfrac{1}{5}\)
c) \(-\dfrac{2}{3}\) : x + \(\dfrac{5}{8}\) = \(-\dfrac{7}{12}\)
Tìm x, biết:
a) \(\dfrac{3}{7}\)x - \(\dfrac{2}{3}\)x = \(\dfrac{10}{21}\)
b) \(\dfrac{7}{35}\) : (x - \(\dfrac{1}{3}\)) = \(-\dfrac{2}{25}\)
c) 3.(x - \(\dfrac{1}{2}\)) - 5. (x + \(\dfrac{3}{5}\)) = -x + \(\dfrac{1}{5}\)
Tìm x, biết:
a) \(\dfrac{1}{20}\) - (x - \(\dfrac{8}{5}\)) = \(\dfrac{1}{10}\)
b) \(\dfrac{7}{4}\) - (x + \(\dfrac{5}{3}\)) = \(\dfrac{-12}{5}\)
c) x - [\(\dfrac{17}{2}\) - \(\left(\dfrac{-3}{7}+\dfrac{5}{3}\right)\)] = \(\dfrac{-1}{3}\)
a) \(\dfrac{2}{3}.x+\dfrac{5}{7}=\dfrac{3}{10}\)
b)\(\dfrac{3}{4}.x-\dfrac{1}{2}=\dfrac{3}{7}\)
Tìm x :
1) \(\left(-0,75x+\dfrac{5}{2}\right).\dfrac{4}{7}-\left(-\dfrac{1}{3}\right)=-\dfrac{5}{6}\)
2) \(\left(4x-9\right)\left(2,5+\dfrac{-7}{3}x\right)=0\)
3) \(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)
4)\(\left(\dfrac{3}{5}-\dfrac{2}{3}x\right)^3=\dfrac{-64}{125}\)
bài 1
a,2-\(\dfrac{2}{3}\)+2,5+\(\dfrac{1}{3}\)+3+\(\dfrac{1}{2}\)
b,\(\dfrac{9}{10}\)-(\(\dfrac{6}{5}\).\(\dfrac{3}{2}\)+\(\dfrac{7}{4}\))
a) \(\dfrac{-4}{7}:x=\dfrac{-2}{5}\)
b) \(\dfrac{2}{3}.x+\dfrac{5}{7}=\dfrac{3}{10}\)
\(b,\dfrac{x}{2}-\left(\dfrac{3x}{5}-\dfrac{13}{5}\right)=-\left(\dfrac{7}{5}+\dfrac{7}{10}.x\right)\)
\(c,\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
\(d,\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
\(e,2\left(x-1\right)=\left(x-1\right)^2\)
a) \(2\dfrac{1}{2}\) - x + \(\dfrac{4}{5}\) = \(\dfrac{2}{3}\) - (\(-\dfrac{4}{7}\) )
b) \(-\dfrac{4}{7}\) - x = \(\dfrac{3}{5}\) - 2x
c) (\(\dfrac{3}{8}\) - \(\dfrac{1}{5}\) ) + (\(\dfrac{5}{8}\) - x) = \(\dfrac{1}{5}\)
A= 5+|\(\dfrac{1}{3}\)-x|
B= 2.|x-\(\dfrac{2}{3}\)|-1
C= |x-2005|+|x-300|
D= |3,7-x|+2,5
