Question

c1:biết x;y;z tỉ lệ với 5;4;3

tính Q=\(\frac{x+2y-3z}{x-2y+3z}\)

c2: cho \(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)tính x/y

Answer 1

c1:Thay số 

Q=\(\frac{5+2.4-3.3}{5-2.4+3.3}\)

O=\(\frac{4}{6}\)=\(\frac{2}{3}\)

 

 

Answer 2

\(\frac{4x}{6y}=\frac{2x+8}{3y+11}\)

\(4x\left(3y+1\right)=6y\left(2x+8\right)\)

\(12xy+4x=12xy+48y\)

\(4x-48y=0\)

\(4x=48y\)

Ta có:\(\frac{4x}{48y}\)

\(\Leftrightarrow\)\(\frac{x}{y}=\frac{1}{12}\)