C=1+53+56+59+...+599
53.C= 53.(1+53+56+59+...+599)
53.C= 53+56+59+512+...+5102
53.C - C=(53+56+59+512+...+5102) - (1+53+56+59+...+599)
53.C - C= 5102-1
C.(53-1)= 5102-1
C = (5102-1) : (53-1)
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C = 1+53+56+59+...+599
53C = 53+56+59+512+....+5102
124C = 53C - C = 5102 - 1
=> C = \(\frac{5^{102}-1}{124}\)
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