Question

`C=(1+2/3)(1+2/5)(1+2/7)...(1+2/2009)(1+2/2011)`

Answer 1

`#P.Vy`

`C=(3/3+2/3)(5/5+2/5)(7/7+2/7)...(2009/2009+2/2009)(2011/2011+2/2011)`

`C=5/3xx7/5xx9/7xx...xx2011/2009xx2013/2011`

\(C=\dfrac{5.7.9\times...\times2011.2013}{3.5.7\times...\times2009.2011}\)

`C=671`

Answer 2

https://olm.vn/hoi-dap/detail/105210184248.html