\(C=\left(1+\frac{1}{1.3}\right)\)\(.\left(1+\frac{1}{2.4}\right)\)\(.\left(1+\frac{1}{3.5}\right)\)\(.\left(1+\frac{1}{2014.2016}\right)\)
\(=\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}...\frac{2015^2}{2014.2016}\)
\(=\frac{2.2}{1.3}.\frac{3.3}{2.4}.\frac{4.4}{3.5}...\frac{2015.2015}{2014.2016}\)
\(=\frac{\left(2.3.4...2015\right).\left(2.3.4...2015\right)}{\left(1.2.3...2014\right).\left(3.4.5...2016\right)}\)
\(=\frac{2015.2}{2016}\)
\(=...\)(tự tinhs)
c= (1+1/1.3).(1+1/2.4).(1+1/3.5)*...*(1+1/2014.2016)
tính m=(1+1/1.3)+(1+1/2.4)+(1+3.5).....(1+1/2014.2016)
tính :(1+1/1.3).(1+1/2.4)+(1+1/3.5)+...+(1+1/2014.2016)
A=2016.(1+1/1.3).(1+1/2.4).(1+1/3.5)...(1+1/2014.2016)
\(\frac{\left(1.3+1\right)\left(2.4+1\right)\left(3.5+1\right).......\left(2014.2016+1\right)}{1.3.2.4.3.5...............2014.2016}\)
Tính C:
C = ( 1+1/1.3)(1+1/2.4)(1+1/3.5).....(1+1/2014.2016)
(Mình đang rất vội nên mong các bạn trả lời sớm. Cảm ơn nhiều!)
Tính:
C=\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2014.2016}\right)\)
tinh
C=\(\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right).\left(1+\frac{1}{3.5}\right)+....+\left(1+\frac{1}{2014.2016}\right)\)
\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2014.2016}\right)\)
