\(\dfrac{x+5}{x-5}-\dfrac{x-5}{x+5}=\dfrac{80x}{x^2-25}\left(x\ne-5;5\right)\)
`⇔`\(\dfrac{\left(x+5\right)^2}{x^2-25}-\dfrac{\left(x-5\right)^2}{x^2-25}=\dfrac{80x}{x^2-25}\)
\(⇒ x ^2 + 10 x + 25 − x ^2 + 10 x − 25 − 80 x = 0\)
\(⇔ ( x ^2 − x ^2 ) + ( 10 x + 10 x − 80 x ) + ( 25 − 25 ) = 0\)
\(⇔ − 60 x = 0\)
\(⇔ x = 0 ( t m )\)