Question

c) (3x+11):8=46

b) 100+(x-23)=317

a) 1002:(x-12)=3

 d) 68-4x=24

e) 110-(4x+15)=3

 

Answer 1

c) (3x + 11) : 8 = 46

=> 3x + 11 = 368

=> 3x = 368 - 11

=> 3x = 357

=> x = 357 : 3

=> x = 119

b) 100 + (x - 23) = 317

=> x - 23 = 317 - 100

=> x - 23 = 217

=> x = 217 + 23

=> x = 240

a) 1002 : (x - 12) = 3

=> x - 12 = 1002 : 3

=> x - 12 = 334

=> x = 334 + 12

=> x = 346

d) 68 - 4x = 24

=> 4x = 68 - 24

=> 4x = 44

=> x = 44 : 4 = 11

e) 110 - (4x + 15) = 3

=> 4x + 15 = 110 - 3

=> 4x + 15 = 107

=> 4x = 107 - 15

=> 4x = 92

=> x = 92 : 4 = 23

Answer 2

a) \(1002:\left(x-12\right)=3\)

\(\Leftrightarrow x-12=1002:3\)

\(\Leftrightarrow x-12=334\)

\(\Leftrightarrow x=334+12\)

\(\Leftrightarrow x=346\)

Vậy \(x=346\)

Answer 3

b) \(100+\left(x-23\right)=317\)

\(\Leftrightarrow x-23=317-100\)

\(\Leftrightarrow x-23=217\)

\(\Leftrightarrow x=217+23\)

\(\Leftrightarrow x=240\)

Vậy \(x=240\)