Question

c) 2/3x²y.(3xy²-x²+6y)

d) 3xy³(2x-3)(2x+3)

Answer 1

\(c,=2x^3y^3-\dfrac{2}{3}x^4y+4x^2y^2\\ d,=3xy^3\left(4x^2-9\right)=12x^3y^3-27xy^3\)

Answer 2

c. \(\dfrac{2}{3x^2y}.\left(3xy^2-x^2+6y\right)\)

= \(\dfrac{2.3xy^2}{3x^2y}-\dfrac{2x^2}{3x^2y}+\dfrac{2.6y}{3x^2y}\)

= \(\dfrac{2y}{x}-\dfrac{2}{3y}+\dfrac{4}{x^2}\)

d. 3xy³(2x - 3)(2x + 3)

= (3x²y³ - 9xy³)(2x + 3)

= 6x³y³ - 9²y³ - 18x²y³ - 27xy³

= 6x³y³ - 27x²y³ - 27xy³