Đặt \(A=1.2.3+2.3.4+........+8.9.10\)
\(\Leftrightarrow A=1.2.\left(3-0\right)+2.3.\left(4-1\right)+......+8.9.\left(10-7\right)\)
\(\Leftrightarrow A=1.2.3-0.1.2+2.3.4-1.2.3+........+8.9.10-7.8.9\)
\(\Leftrightarrow A=8.9.10\)
\(\Leftrightarrow A=720\)
Ta có ; A = 1.2.3 + 2.3.4 + ..... + 8.9.10
=> 6A = 1.2.3.4 - 1.2.3.4 + 2.3.4.5 - 2.3.4.5 + ..... + 8.9.10.11
=> 6A = 8.9.10.11
=> A = \(\frac{\text{8.9.10.11}}{6}=1320\)