Question

C= ( 1+1/2)x(1+1/3)x(1+1/4)x...x ( 1+1/2013)

giải hộ mik với

Answer 1

\(C=\left(\dfrac{2}{2}+\dfrac{1}{3}\right)\times\left(\dfrac{3}{3}+\dfrac{1}{3}\right)\times\left(\dfrac{4}{4}+\dfrac{1}{4}\right)\times...\times\left(\dfrac{2013}{2013}+\dfrac{1}{2013}\right)\)

\(C=\dfrac{3}{2}\times\dfrac{4}{3}\times\dfrac{5}{4}\times....\times\dfrac{2014}{2013}\)

\(C=\dfrac{2014}{2}=1007\)

Answer 2

`C = (2/2 + 1/3) xx (3/3 + 1/3) xx (4/4 + 1/4) xx ... xx (2013/2013 + 1/2013)`

`C = 3/2 xx 4/3 xx 5/4 xx ... xx 2014/2013`

`C = 2014/2 = 1007`

Vậy `C = 1007`

Answer 3

tại sao lại có 2014/2