Question

`b)y:0,25+y:0,5+y:0,01=53`

Answer 1

`#P.Vy`

`y:0,25+y:0,5+y:0,01=53`

`y×4+y×2+y×100=53`

`y×(4+2+100)=53`

`y×106=53`

`y=53:106`

`y=1/2`

Answer 2

\(y:0,25+y:0,5+y:0,01=53\)

\(y\times4+y\times2+y\times100=53\)

\(y\times\left(100+4+2\right)=53\)

\(y\times106=53\)

\(y=53:106\)

\(y=\)\(\dfrac{1}{2}\)

Answer 3

y : 0,25 + y : 0,5 + y : 0,01 = 53

y x 4 + y x 2 + y x 100 = 53

y x (4 + 2 + 100) = 53

y x 106 = 53

y = 53/106