Question

bỏ ngoặc rồi thu gọn biểu thức;

(a+b)-(a-b)+(a-c)-(a+c)

(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)

 

Answer 1

a/ = a + b - a+b + a-c-a-c

= 0 - 0 + 0 - 0

= 0

Answer 2

a/ = a + b - a + b + a - c - a - c = 2b - 2c

b/ = a + b - c + a - b + c - b - c + a - a + b + c = 2a

Answer 3

Ta có:(a+b)-(a-b)+(a-c)-(a+c)

=a+b-a+b+a-c-a-c

=2b-2c

Ta có:(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)

=a+b-c+a-b+c-b-c+a-a+b+c

=2a

=

Answer 4

a)=a+b-a-b+a-c-a-c

=(a-a)+(b+b)+(a-a)+(-c-c)

=0+2b+0+2c

=0+0+2(b+c)

=2(b+c)