a, A=(a-b)-(a-b+c)
=a-b-a+b-c
=(a-a)+(b-b)-c
= 0 + 0 - c
=-c
b, B=(a+b+c)-(a+b-c)
=a+b+c-a-b+c
=(a-a)+(b-b)+(c+c)
=0+0+2c
=2c
t**k cho mình nha!!
chúc hok tốt!!
a) \(A=\left(a-b\right)-\left(a-b+c\right)\)
\(=a-b-a+b-c\)
\(=\left(a-a\right)+\left(b-b\right)-c\) \(=-c\)
b) \(B=\left(a+b+c\right)-\left(a+b-c\right)\)
\(=a+b+c-a-b+c\)
\(=\left(a-a\right)+\left(b-b\right)+\left(c+c\right)\)
\(=2c\)
bB = a + b + c - a - b + c
= a - a + [(b + c ) - ( b + c )]
= 0 + 0
= 0
Mk ko biết đung hay sai nữa!
Sory nhé ,chỉ giúp đươc câu bB thui