\(\left|a+7\right|^{2017}+\left|b-3\right|^{2016}=0\)
\(\Rightarrow\orbr{\begin{cases}\left|a+7\right|^{2017}=0\\\left|b-3\right|^{2016}=0\end{cases}\Rightarrow\orbr{\begin{cases}a=-7\\b=3\end{cases}}}\)
Khi đó \(a-b=\left(-7\right)-3=-10\)
Ta có:
\(\left|a+7\right|^{2017}\ge0;\left|b-3\right|^{2016}\ge0\)
\(\Rightarrow\left|a+7\right|^{2017}+\left|b-3\right|^{2016}\ge0\)
Mà \(\left|a+7\right|^{2017}+\left|b-3\right|^{2016}=0\)(theo đề bài)
\(\Rightarrow\hept{\begin{cases}\left|a+7\right|^{2017}=0\\\left|b-3\right|^{2016}=0\end{cases}\Rightarrow\hept{\begin{cases}\left|a+7\right|=0\\\left|b-3\right|=0\end{cases}\Rightarrow}\hept{\begin{cases}a+7=0\\b-3=0\end{cases}\Rightarrow}\hept{\begin{cases}a=-7\\b=3\end{cases}}}\)
\(\Rightarrow a-b=-7-3=-10\)
Vậy a-b=-10
đ/s -10 nhe
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