chung minh rang ty le thuc\(\frac{a}{b}\)=\(\frac{c}{d}\)(a-b khong =0,c-d khong =0) ta co the suy ra ti le thuc \(\frac{a+b}{a-b}\)=\(\frac{c+d}{c-d}\)
cho ti le thuc \(\frac{a}{b}\)=\(\frac{c}{d}\)
chung minh rang\(\frac{a}{b}\)=\(\frac{7a+5c}{7b+5d}\)[b+d khac 0]
cac ban co biet tai sao minh go dau cac chu cai thi chu cai do va dau deu bien mat khong? giup minh voi , cau hoi tren la 1 vi du
Chung minh rang neu a^2=bc thi
a) \(\frac{a+b}{a-b}=\frac{c+a}{c-a}\)
b) \(\frac{a^2+c^2}{b^2+a^2}=\frac{c}{b}\)
\(cho\frac{a}{b}=\frac{c}{d} chung minh \frac{2a-3b}{5b}=\frac{2c-3d}{5d} khong duoc su dung cach \frac{a}{b}=\frac{c}{d}=k\)
cho tam giac ABC biet goc A=120o ;BC=a ;AC=b ;AB=c
chung minh rang a^2=b^2+c^2+bc
a)cho biet : a+b/a-b=c+a/c-a
chứng minh rằng : a^2=bc
b) cho 4 so kha c0 : a1;a2;a3;a4 thoa man a2^2= a1.a3
a3^2= a2.a4
cmr :
\(\frac{a1^3+a2^3+a3^3}{a2^3+a3^3+a4^3}=\frac{a1}{a4}\)
Cho\(\frac{a}{c}=\frac{c}{b}\)Chung minh rang \(\frac{a^2+c^2}{b^2+c^2}=\frac{a}{b}\)
giup em voi
cho ti le thuc \(\frac{a+b}{b+c}=\frac{c+d}{d+a}\)
chung minh rang |a| = |c| hoac |a+b| +|c=d|
ai lam nhanh nhat, dung nhat em tick choa
cho\(\frac{a}{b}=\frac{b}{c}=\frac{b}{d}\)chung minh rang\(a=b=c\)