Question

Biết \(A=12.5+\frac{1}{4}+234.567x2.5\)

và \(B=25.34x23.23-495.05\)

và \(C=A+B-2345.6789+332.5\)

Hãy so sánh \(A,B,C?\)(\(x\)là dấu nhân)

Answer 1

\(A=12.5+\frac{1}{4}+234.567\times2.5=12,5+\frac{1}{4}+586,4175=12,75+586,4175=599,1675\)

\(B=25,34\times23,23-495,05=588,6482-495,05=93,5982\)

\(C=599,1675+93,5982-2345,6789+332,5=692,7657-2345,6789+332,5=-1652,9132+332,5=-1320,4132\)

\(\Rightarrow A>B>C\)

Answer 2

A=599.1675

B=477175

C=?

Answer 3

Answer 4

\(A=599,1675\)'

\(B=477175\)

\(C=475760,9886\)

Answer 5

a=599,1675

b=477175

c=475760,9886

Answer 6

Answer 7

Các số phải tìm là:

A=599,1675

B=477175

C=??