Ta có :
\(B=\frac{3^2.5^2.7^2.3^3.7^2}{3^2.5^2.7^4}=\frac{3^4.5^2.7^4}{3^2.5^2.7^4}=\frac{3^4}{3^2}=3^2=9\)
Vậy B = 9.
k nha bạn
B=\(\frac{\left(9.25.49\right).\left(9.49\right)}{735^2}\)
B=\(\frac{11025.441}{540225}\)
B=\(\frac{4862025}{540225}\)
B=9