Question

B=\(\frac{9^5.27^3}{3^{18}}\)

Answer 1

\(\frac{9^5.27^3}{3^{18}}=\frac{\left(3^2\right)^5.\left(3^3\right)^3}{3^{18}}=\frac{3^{10}.3^9}{3^{18}}=\frac{3^{19}}{3^{18}}=3^{19-18}=3^1=3\)

k mk nha !

Answer 2

\(\frac{9^5.27^3}{3^{18}}=\frac{\left(3^2\right)^5.\left(3^3\right)^3}{3^{18}}=\frac{3^{10}.3^9}{3^{18}}=3^{19-18}=3^1=3.\)