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giải/hệ/pt
\(\dfrac{96}{x+y}+\dfrac{96}{x-y}=14\)
\(\dfrac{96}{x+y}+\dfrac{72}{x-y}=\dfrac{24}{y}\)
9 tháng 2 2023 lúc 21:21
\(\left\{{}\begin{matrix}\dfrac{120}{x}=\dfrac{80}{y}\\\dfrac{96}{x}+1=\dfrac{104}{y}\end{matrix}\right.\) giải hệ
Giải hệ\(\begin{cases} \dfrac{xy}{x+y}=\dfrac{2}{3}\\ \dfrac{yz}{y+z}=\dfrac{3}{2}\\ \dfrac{xz}{x+z}=\dfrac{6}{7} \end{cases} \)
7 tháng 9 2020 lúc 15:13
Cho a , b, c , p , q ,r đôi một khác nhau . Giải hệ :
\(\begin{cases} &\\\dfrac{x}{a-q}+\dfrac{y}{b-q}+\dfrac{z}{c-q}=1\\&\\\dfrac{x}{a-p}+\dfrac{y}{b-p}+\dfrac{z}{c-p}=1\\&\\\dfrac{x}{a-r}+\dfrac{y}{b-r}+\dfrac{z}{c-r}=1\\& \end{cases} \)
\(\left\{{}\begin{matrix}\dfrac{3}{x-1}-\dfrac{1}{y+2}=\dfrac{3}{4}\\\dfrac{5}{x-1}+\dfrac{3}{y+2}=\dfrac{29}{12}\end{matrix}\right.\)giải chi tiết giúp mình nha☘⚽✿❤ mình cảm ơn nha
Giải hệ PT sau:
\(\begin{cases} \dfrac{1}{2}x - y = 1\\ x - 2y = 2 \end{cases}\)
25 tháng 11 2023 lúc 23:17
Giải hpta)left{{}begin{matrix}dfrac{2x}{x+1}+dfrac{y}{y+1}2dfrac{x}{x+1}+dfrac{3}{y+1}-1end{matrix}right.b)left{{}begin{matrix}dfrac{x}{y}-dfrac{x}{y+12}1dfrac{x}{y+12}-dfrac{x}{y}2end{matrix}right.c)left{{}begin{matrix}dfrac{x+y}{xy}+dfrac{xy}{x+y}dfrac{5}{2}dfrac{x-y}{xy}+dfrac{xy}{x-y}dfrac{10}{3}end{matrix}right.d)left{{}begin{matrix}dfrac{2x}{y-1}+dfrac{3y}{x-1}1dfrac{2y}{x-1}-dfrac{5x}{y-1}2end{matrix}right.
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Giải hpt
a)\(\left\{{}\begin{matrix}\dfrac{2x}{x+1}+\dfrac{y}{y+1}=2\\\dfrac{x}{x+1}+\dfrac{3}{y+1}=-1\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{x}{y}-\dfrac{x}{y+12}=1\\\dfrac{x}{y+12}-\dfrac{x}{y}=2\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}\dfrac{x+y}{xy}+\dfrac{xy}{x+y}=\dfrac{5}{2}\\\dfrac{x-y}{xy}+\dfrac{xy}{x-y}=\dfrac{10}{3}\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}\dfrac{2x}{y-1}+\dfrac{3y}{x-1}=1\\\dfrac{2y}{x-1}-\dfrac{5x}{y-1}=2\end{matrix}\right.\)
22 tháng 1 lúc 19:59
Giải hệ phương trình:
a) \(\left\{{}\begin{matrix}\dfrac{x}{35}-y=2\\y-\dfrac{x}{50}=1\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{1}{16}\\\dfrac{3}{x}+\dfrac{6}{y}=\dfrac{1}{4}\end{matrix}\right.\)
26 tháng 11 2023 lúc 15:22
Giải hpta)left{{}begin{matrix}dfrac{4}{2x-3y}+dfrac{5}{3x+y}-2dfrac{3}{3x+y}-dfrac{5}{2x-3y}21end{matrix}right.b)left{{}begin{matrix}dfrac{7}{x-y+2}-dfrac{5}{x+y-1}dfrac{9}{2}dfrac{3}{x-y+2}+dfrac{2}{x+y-1}4end{matrix}right.c)left{{}begin{matrix}dfrac{3}{2x-y}-dfrac{6}{x+y}-1dfrac{1}{2x-y}-dfrac{1}{x+y}0end{matrix}right.d)left{{}begin{matrix}dfrac{4}{x+y-1}-dfrac{5}{2x-y+3}dfrac{5}{2}dfrac{3}{x+y-1}+dfrac{1}{2x-y+3}dfrac{7}{5}end{matrix}right.e)left{{}begin{matrix}dfrac{6}{x-2y}+dfrac{2}{x+2y}3d...
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Giải hpt
a)\(\left\{{}\begin{matrix}\dfrac{4}{2x-3y}+\dfrac{5}{3x+y}=-2\\\dfrac{3}{3x+y}-\dfrac{5}{2x-3y}=21\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{7}{x-y+2}-\dfrac{5}{x+y-1}=\dfrac{9}{2}\\\dfrac{3}{x-y+2}+\dfrac{2}{x+y-1}=4\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}\dfrac{3}{2x-y}-\dfrac{6}{x+y}=-1\\\dfrac{1}{2x-y}-\dfrac{1}{x+y}=0\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}\dfrac{4}{x+y-1}-\dfrac{5}{2x-y+3}=\dfrac{5}{2}\\\dfrac{3}{x+y-1}+\dfrac{1}{2x-y+3}=\dfrac{7}{5}\end{matrix}\right.\)
e)\(\left\{{}\begin{matrix}\dfrac{6}{x-2y}+\dfrac{2}{x+2y}=3\\\dfrac{3}{x-2y}+\dfrac{4}{x+2y}=-1\end{matrix}\right.\)