b/\(\dfrac{3}{4}:x=-\dfrac{5}{8}\)
\(x=\dfrac{3}{4}:\left(-\dfrac{5}{8}\right)\)
\(x=-\dfrac{6}{5}\)
c/\(\dfrac{6}{-x}=\dfrac{3}{4}\)
\(-3x=6\cdot4\)
\(x=-\dfrac{6\cdot4}{3}\)
\(x=-8\)
#DatNe
\(b)\dfrac{3}{4}:x=-\dfrac{5}{8}\\ x=\dfrac{3}{4}:-\dfrac{5}{8}\\ x=-\dfrac{6}{5}\\ c)\dfrac{6}{-x}=\dfrac{3}{4}\\ -x=\dfrac{6\times4}{3}\\ -x=8\\x=-8.\)
`b)`
\(\dfrac{3}{4}:x=-\dfrac{5}{8}\\ x=\dfrac{3}{4}:\left(-\dfrac{5}{8}\right)\\ x=\dfrac{3}{4}\times\dfrac{-8}{5}\\ x=-\dfrac{6}{5}\\ c,\\ \dfrac{6}{-x}=\dfrac{3}{4}\\ -3x=24\\ x=-8\)
`b)3/4:x=-5/8`
`=>x=3/4:(-5/8)`
`=>x=3/4 .(-8/5)`
`=>x=-24/20`
`=>x=-6/5`
Vậy `x=-6/5`
__
`c)6/(-x)=3/4`
`=>(-6)/x=3/4`
`=>(-6)/x=(3.(-2))/(4.(-2))`
`=>(-6)/x=(-6)/(-8)`
`=>x=-8`
Vậy `x=-8`