Question

bài1:tính bằng cách thuận tiện nhất 

a,64x23+37x23-23+6,24

b,33,76+19,52+6,24

c,38/11+(16/13+6/11)

d,3/4:3/5-1/5

Answer 1

a/64 x 23 + 37 x 23 - 23 + 6,24
= ( 64 + 37 - 1 ) x 23 + 6,24
= 100 x 23 + 6,24
= 2300 + 6,24
= 2306,24
b/33,76 + 19,52 + 6,24
= ( 33,76 + 6,24 ) + 19,52
= 40 + 19,52
= 59,52
c/\(\dfrac{38}{11}+\left(\dfrac{16}{13}+\dfrac{6}{11}\right)\)
\(=\dfrac{38}{11}+\dfrac{16}{13}+\dfrac{6}{11}\)
\(=\left(\dfrac{38}{11}+\dfrac{6}{11}\right)+\dfrac{16}{13}\)
\(=4+\dfrac{16}{13}\)
\(=\dfrac{52}{13}+\dfrac{16}{13}\)
\(=\dfrac{68}{13}\)
d/\(\dfrac{3}{4}:\dfrac{3}{5}-\dfrac{1}{5}\)
\(=\dfrac{3}{4}\times\dfrac{5}{3}-\dfrac{1}{5}\)
\(=\dfrac{5}{4}-\dfrac{1}{5}\)
\(=\dfrac{25}{20}-\dfrac{4}{20}\)
\(=\dfrac{21}{20}\)
#AvoidMe