Question

Bài 5: Tìm x;y;z biết: |3x-5|+\(\left(2y+5\right)^{208}\)\(\left(4z-3\right)^{20}\)≤0

Answer 1

Sửa đề \(\left|3x-5\right|+\left(2y+5\right)^{208}+\left(4x-3\right)^{20}\le0\)

Mà \(\left|3x-5\right|\ge0\);\(\left(2y+5\right)^{208}\ge0;\left(4x-3\right)^{20}\ge0\)

Do đó \(\left|3x-5\right|+\left(2y+5\right)^{208}+\left(4z-3\right)^{20}=0\)

\(\Rightarrow\left\{{}\begin{matrix}3x-5=0\\2y+5=0\\4z-3=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5}{3}\\y=-\dfrac{5}{2}\\z=\dfrac{3}{4}\end{matrix}\right.\)