C1: \(\left(\frac{3}{5}+\frac{4}{9}\right)\cdot\frac{3}{8}=\frac{47}{45}\cdot\frac{3}{8}=\frac{141}{360}=\frac{47}{120}\)
C2: \(\left(\frac{3}{5}+\frac{4}{9}\right)\cdot\frac{3}{8}=\frac{3}{5}\cdot\frac{3}{8}+\frac{4}{9}\cdot\frac{3}{8}=\frac{9}{40}+\frac{12}{72}=\frac{47}{120}\)
C1: ( \(\frac{3}{5}+\frac{4}{9}\) ) * \(\frac{3}{8}\)
= \(\frac{47}{45}\) * \(\frac{3}{8}\) = \(\frac{47}{120}\)
C2: Đề
= 3/5 * 3/8 + 4/9 * 3/8
= 9/40 + 1/6
= 47/120
\(C1:(\frac{3}{5}+\frac{4}{9})\times\frac{3}{8}=(\frac{27}{45}+\frac{20}{45})\times\frac{3}{8}=\frac{47}{45}\times\frac{3}{8}=\frac{47}{120}\)
C2 : Dùng tính chất phân phối của phép nhân đối với phép cộng
\((\frac{3}{5}+\frac{4}{9})\times\frac{3}{8}=\frac{3}{5}\times\frac{3}{8}+\frac{4}{9}\times\frac{3}{8}=\frac{9}{40}+\frac{1}{6}=\frac{27}{120}+\frac{20}{120}=\frac{47}{120}\)