Question

Bài 2:Tính tổng

a) \(\frac{1}{2x3}+\frac{1}{3x4}+....+\frac{1}{49x50}\)

 

Answer 1

=1/2-1/3+1/3-1/4+.....+1/49+1/50

=1/2-1/50

=25/50-1/50

=24/50

=12/25

Answer 2

\(\frac{1}{2x3}\)+   \(\frac{1}{3x4}\)+  ...  +  \(\frac{1}{49x50}\)

= \(\frac{1}{2}\)-  \(\frac{1}{3}\)+  \(\frac{1}{3}\)-  \(\frac{1}{4}\)+  ...  +  \(\frac{1}{49}\)-  \(\frac{1}{50}\)

=  \(\frac{1}{2}\)-  \(\frac{1}{50}\)

=\(\frac{12}{25}\)

Answer 3

\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}+...+\frac{1}{49}-\frac{1}{50}\)

\(=\frac{1}{2}-\frac{1}{50}\)

=\(=\frac{12}{15}\)

Answer 4

tổng bằng 12/15

Answer 5

kết quả là 12/25:không phải là 12/15