d,155-10(x+1)=55
10(x+1) = 155 - 55
10(x+1) = 100
x+1 = 100 : 10
x+1 = 10
x = 10 - 1 =9
e,6(x+\(2^3\))+40=100
6(x+\(2^3\)) = 100 - 40
6(x+\(2^3\)) = 60
(x+\(2^3\)) = 60 : 6
(x+\(2^3\)) = 10
x = 10 - \(2^3\)
x = 10 - 8 = 2
f,\(2^2\)(x+\(3^2\))-5=55
\(2^2\)(x+\(3^2\)) = 55 + 5
\(2^2\)(x+\(3^2\)) = 60
(x+\(3^2\)) = 60 : \(2^2\)
(x+\(3^2\)) = 60 : 4
(x+\(3^2\)) = 15
x + 9 = 15
x = 15-9=6.
Hok tốt !
d) \(155-10\left(x+1\right)=55\)
\(\Rightarrow10\left(x+1\right)=155-55\)
\(\Rightarrow10\left(x+1\right)=100\)
\(\Rightarrow x+1=100:10\)
\(\Rightarrow x+1=10\)
\(\Rightarrow x=10-1\)
\(\Rightarrow x=9\)
Vậy x = 9
e) \(6\left(x+2^3\right)+40=100\)
\(\Rightarrow6\left(x+2^3\right)=100-40\)
\(\Rightarrow6\left(x+2^3\right)=60\)
\(\Rightarrow x+2^3=60:6\)
\(\Rightarrow x+2^3=10\)
\(\Rightarrow x+8=10\)
\(\Rightarrow x=10-8\)
\(\Rightarrow x=2\)
Vậy x = 2
f) \(2^2\left(x+3^2\right)-5=55\)
\(\Rightarrow2^2\left(x+3^2\right)=55+5\)
\(\Rightarrow2^2\left(x+3^2\right)=60\)
\(\Rightarrow4\left(x+9\right)=60\)
\(\Rightarrow x+9=60:4\)
\(\Rightarrow x+9=15\)
\(\Rightarrow x=15-9\)
\(\Rightarrow x=6\)
Vậy x = 6
\(d,155-10\left(x+1\right)=55\) \(e,6\left(x+2^3\right)+40=100\)
\(\Rightarrow10\left(x+1\right)=155-55\) \(\Rightarrow\left(x+2^3\right)+40=100:6\)
\(\Rightarrow10\left(x+1\right)=100\) ủa hình như câu này sai đề thì phải ??-.-'''
\(\Rightarrow x+1=100:10\)
\(\Rightarrow x+1=10\)
\(\Rightarrow x=10-1=9\)
à nhầm ha=.="'
\(e,6\left(x+2^3\right)+40=100\)
\(\Rightarrow6\left(x+2^3\right)=100-40\)
\(\Rightarrow6\left(x+2^3=\right)60\)
\(\Rightarrow x+2^3=60:6\)
\(\Rightarrow x+8=10\)
\(\Rightarrow x=2\)
\(\left(d\right)155-10\left(x+1\right)=55\)
\(10\left(x+1\right)=155-55\)
\(10\left(x+1\right)=100\)
\(x+1=100:10\)
\(x+1=10\)
\(x=10-1\)
\(x=9\)
\(\left(e\right)6\left(x+2^3\right)+40=100\)
\(6\left(x+2^3\right)=100-40\)
\(6\left(x+2^3\right)=60\)
\(x+2^3=60:6\)
\(x+8=10\)
\(x=10-8=2\)
\(\left(f\right)2^2\left(x+3^2\right)-5=55\)
\(2^2\left(x+3^2\right)=55+5\)
\(2^2\left(x+3^2\right)=60\)
\(x+3^2=60:4\)
\(x+3^2=15\)
\(x=15-9=6\)
Chúc bạn hok tốt !!!