a, 72-(4.x+15)=45 con cau b khong lam dc
4.x+15=72-45
4.x+15=27
4.x=27-15
4.x=8
x=8:4
x=2
a, 72-(4x+15)=45
4x+15=72-45
4x+15=27
4x =27-15
4x =12
x =3
b,7.(x+5^2)-20=190
7.(x+25) =190+20
7.(x+25) =210
x+25 =210:7
x+25 =30
x =30-25
x =5
chúc bạn học tốt nhé!
a,72-(4x+15)=45
\(4x+15=72-45\)
\(4x+15=27\)
\(4x=27-15\)
\(4x=12\)
\(\Rightarrow x=3\)
b,7.(x+5^2)-20=190
\(7.\left(x+5^2\right)=190+20\)
\(7.\left(x+5^2\right)=210\)
\(\Rightarrow x+25=30\)
\(\Rightarrow x=5\)
HỌC TỐT
a)72-(4x+15)=45
=>(4x+15)=72-45
=>(4x+15)=27
=>4x=27-15
=>4x=12
=>x=12:4
=>x=3
b)7(x+52)-20=190
=>7(x+52)=190+20
=>7(x+52)=210
=>(x+52)=210:7
=>(x+52)=30
=>x=30-(52)
=>x=30-25
=>x=5
a) 72 - ( 4x + 15 ) = 45 b) 7. ( x + 52) - 20 = 190
4x + 15 = 72 - 45 7. ( x + 52) = 190 + 20
4x + 15 = 27 7. ( x + 52) = 210
4x = 27- 15 ( x + 52) = 210 : 7
4x = 12 x + 52 = 30
x = 12 : 4 x + 25 = 30
x = 3 x = 30 - 25
x = 5
a)\(72-\left(4x+15\right)=45\)
\(4x+15=72-45\)
\(4x+15=27\)
\(4x=27-15\)
\(4x=12\)
\(x=3\)
Vậy \(x=3\)
b) \(7\left(x+5^2\right)-20=190\)
\(7\left(x+25\right)=190+20\)
\(7\left(x+25\right)=210\)
\(x+25=30\)
\(x=5\)
Vậy \(x=5\)
a)72-(4x+15)=45 b)7.(x+52)-20=190
4x+15 =72-45=27 7.(x+52) =190+20=210
4x =27-15=12 x+25 =210:7=30
x =12:4=3 x =30-25=5