Question

Bài 2 : Thực hiện phép tính ( tính hơp lý nếu có thể )

a) 125% . \(\left(\frac{-1}{2}\right)^2\): \(\left(1\frac{5}{6}-1,5\right)+2016^0\)

Answer 1

\(125\%\cdot\left(-\frac{1}{2}\right)^2\div\left(1\frac{5}{6}-1,5\right)+2016^0\)

\(=\frac{125}{100}\cdot\frac{1}{4}\div\left(\frac{11}{6}-\frac{3}{2}\right)+1\)

\(=\frac{5}{4}\cdot\frac{1}{4}\div\left(\frac{11}{6}-\frac{9}{6}\right)+1\)

\(=\frac{5}{16}\div\frac{2}{6}+1\)

\(=\frac{15}{16}+1=\frac{31}{16}\)

Answer 2

         \(125\%.\left(\frac{-1}{2}\right)^2:\left(1\frac{5}{6}-1,5\right)+2016^0\)

\(=\frac{125}{100}.\frac{1}{4}:\left(\frac{11}{6}-\frac{3}{2}\right)+1\)

\(=\frac{5}{16}:\left(\frac{11}{6}-\frac{9}{6}\right)+1\)

\(=\frac{5}{16} :\frac{1}{3}+1\)

\(=\frac{5}{16} .\frac{3}{1}+1\)

\(=\frac{15}{16}+1\)

\(=\frac{31}{16}\)

Answer 3

125% . \(\left(\frac{-1}{2}\right)^2:\left(1\frac{5}{6}-1,5\right)+2016^0\)

= 125 . \(\frac{1}{4}\div\left(\frac{11}{6}-\frac{3}{2}\right)+1\)

= \(\frac{5}{4}\). \(\frac{1}{4}\div\left(\frac{11}{6}-\frac{9}{6}\right)+1\)

= \(\frac{5}{16}\div\frac{2}{6}+1\)

=\(\frac{15}{16}+1=\frac{31}{16}\)

Answer 4

31/16 nha