a)\(x=\frac{3}{4}-\frac{1}{3}\)
\(x=\frac{5}{12}\)
Vậy...
b)\(x=\frac{5}{7}+\frac{2}{5}\)
\(x=\frac{39}{35}\)
Vậy...
c)\(-x=\frac{6}{7}+\frac{2}{3}\)
\(-x=\frac{32}{21}\)
\(x=\frac{-32}{21}\)
Vậy...
d)\(-x=\frac{1}{3}-\frac{4}{7}\)
\(-x=\frac{-5}{21}\)
\(x=\frac{5}{21}\)
Vậy...
tk mk nhoaa bn
Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
Bài 1: Thực hiện phép tính:
a, \(3\frac{1}{2}-\frac{1}{2}.\left(-4,25-\frac{3}{4}\right)^2:\frac{5}{4}\)
b, \(\frac{3}{7}.1\frac{1}{2}+\frac{3}{7}.0,5-\frac{3}{7}.9\)
c, \(\frac{125^{2016}.8^{2017}}{50^{2017}.20^{2018}}\)
d, \(\frac{4^{2002}.9^{1001}}{16^{1001}.3^{2003}}\)
e, \(\sqrt{25-16}-\left|-3,7+0,7\right|\)
Bài 2: Tìm x
a, \(\frac{1}{3}x+\frac{4}{5}=3\frac{4}{5}\)
b, \(\left|x+\frac{3}{4}\right|-2,25=1\frac{3}{4}\)
c, \(\left(-x+\frac{2}{5}\right)^4=\frac{1}{16}\)
d, \(\left(\frac{2}{5}\right)^{3x}:\left(\frac{4}{3}\right)^{21}=\left(\frac{6}{20}\right)^{21}\)
e, \(\frac{-x}{\frac{3}{5}}=\frac{\frac{27}{5}}{-x}\)
g, \(x:1\frac{1}{2}=-2,5:2\frac{1}{5}\)
Tìm x, biết:
a) 60%x + 0,4x + x :3 =2
b)1-\(\left(5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16\frac{2}{3}\right)\)
c)\(3\frac{1}{4}x-\frac{7}{6}x=\frac{-5}{12}+1\frac{2}{3}\)
Bài 2: Tính:
a) A= \(\frac{-45.58-45.42}{2+4+6+...+16+18}\)
b)1-2-3+4+5-6-7+...+601-602-603+604
b) \(\frac{\left(140\frac{3}{7}-138\frac{5}{12}\right):18\frac{1}{6}}{0,002}\)
Bài 3: Cho A và B, biết:
A=\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\) và B= \(\frac{4}{35}+\frac{4}{63}+\frac{4}{99}+\frac{4}{143}+\frac{4}{195}\)
Hãy so sánh A & B
Bài 1: Tìm x:
a)\(\frac{3}{4}+\frac{2}{5}x=\frac{29}{60}\)
b)\(1\frac{3}{4}\cdot x+1\frac{1}{2}=-\frac{4}{5}\)
c)\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)
d)\(2\frac{3}{4}x=3\frac{1}{7}:0,01\)
e)\(2x\cdot\left(x-\frac{1}{7}\right)=0\)
Bai1:tìm x biết
a, (\(\frac{1}{7}\)\(\cdot\) x -\(\frac{2}{7}\))(-\(\frac{1}{5}x+\frac{3}{5}\))(\(\frac{1}{3}\cdot x+\frac{4}{3}\))
b, \(\frac{1}{6}\cdot x+\frac{1}{10}\cdot x-\frac{4}{5}\cdot x+1=0\)
c,(\(x-\frac{2}{9}\))^3=(\(\frac{2}{3}\))^6
d, (x-7)^x+1-(x-7)^x+11=0
tìm x biết
a,\(\left(152\frac{2}{4}-148\frac{3}{8}\right):0,2=x:0,3\)
b,\(\left(85\frac{7}{30}-83\frac{5}{18}\right):2\frac{2}{3}=0,01x:4\)
c,\(\frac{x-1}{x+5}=\frac{6}{7}\)
d,\(\frac{x^2}{6}=\frac{24}{25}\)
e,\(\frac{x-2}{x-1}=\frac{x+4}{x+7}\)
g\(\frac{x-3}{x+5}=\frac{5}{7}\),
bài 1: cho x, y thuộc Q. cmr:
|x + y| =< |x| + |y|
bài 2: tính:
\(A=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
bài 3: cho a + b + c = a^2 + b^2 + c^2 = 1 và x : y : z = a : b : c.
cmr: (x + y + z)^2 = x^2 + y^2 + z^2
Tìm x,biết
a)\(|x+\frac{1}{3}|=0\)
b)\(|x+\frac{3}{4}=\frac{1}{2}|\)
c)\(|\frac{5}{18}-x|-\frac{7}{24}=0\)
d)\(\frac{2}{5}-|\frac{1}{2}-x|=6\)
e)\(|\frac{3}{8}-x|+\frac{5}{6}=\frac{7}{4}\)
Bài 1:
a) \(\left(2x-3\right)\left(x^2+0,75\right)=0\)
b)\(\frac{x+3}{-2}=\frac{-8}{x+3}\)
c) \(\left(\frac{1}{2}\cdot x-1\right)^2=\frac{16}{81}\)
d) \(2^{x+1}-2^x=8\)
e) \(\frac{2x-3}{5}=\frac{4x+3}{-7}\)
BÀI 2:
a) x:y:z=3:(-5):7 và 2z-3y-x=4
b) 3x=5y=6z và x-y-2z=4
c)$\frac{x}{2}=\frac{y}{3};\frac{y}{5}=\frac{z}{7}$ và 2x+y-z=-14
d)$\frac{x}{2}=\frac{y}{3}=\frac{z}{5}$ và 3y+x-z=4
