Mong mọi người giúp mk giải 3 câu này Cảm ơn rất nhiều
Chứng minh rằng
a)1+ 1/2 mũ 2 + 1/3 mũ 2 + 1/4 mũ 2+...+1/100 mũ 2 < 2
b)1+1/2+1/3+1/4+...+1/63<6
c)1/2 . 3/4 . 5/6... 9999/10000 < 1/100
B1:Tính tổng S=1+2+2^2+2^3+....+2^2008/1-2^2009
B2:Chứng minh rằng:
a,A=1+1/2^2+1/3^2+1/4^2+...+1/100^2 <2
b,B=1+1/2+1/3+1/4+...+1/63<6
c,C=1/2*3/4*5/6*...*9999/10000 ,1/100
Bài 1 : Chứng minh
a) \(A=1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{100^2}< 2\)
b) \(B=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{63}< 6\)
c) \(C=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}.\frac{7}{8}...\frac{9999}{10000}< \frac{1}{100}\)
Chứng minh rằng
a, B= 1+1/2+1/3+1/4+....+1/63 <6
b, C =1/2.3/4.5/6.....9999/10000 <1/100
a) \(A=1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{2014^2}< 2^{ }\)
b)\(B=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{63}< 6\)
c)\(C=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}.....\frac{9999}{10000}< \frac{1}{100}\)
Chứng minh rằng:
a) A=1+1/2^2+1/3^2+1/4^2+...+1/100^2 bé hơn 2
b) B=1+1/2+1/3+1/4+...+1/63 bé hơn 6
c)M=1/3+1/31+1/35+1/37+ 1/47+1/53+1/61 bé hơn 1/2
d)C=1/2.3/4.5/6....9999/10000 bé hơn 1/100
Bài 1: Tìm x, biết:
\(\frac{1}{2.3}x+\frac{1}{3.4}x+\frac{1}{4.5}x+.....+\frac{1}{49.50}x=1\)
Bài 2: Chứng minh rằng:
\(a)A=1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+.....+\frac{1}{100^2}< 2\)
\(b)B=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.....+\frac{1}{63}< 6\)
\(c)C=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}.......\frac{9999}{10000}< \frac{1}{100}\)
Bài 3: Tính tổng:
\(S=\frac{1+2+2^2+2^3+.....+2^{2008}}{1-2^{2009}}\)
CMR: C = 1/2 . 3/4 . 5/6 ..... 9999/10000 < 1/100
cho A=1/2*3/4*5/6*...*9999/10000. chứng minh rằng A <1/100