\(\frac{1}{24.25}+\frac{1}{25.26}+\frac{1}{26.27}+...+\frac{1}{29.30}+y:\frac{1}{3}=-4\)
\(\frac{1}{24}-\frac{1}{25}+\frac{1}{25}-\frac{1}{26}+\frac{1}{26}-\frac{1}{27}+...+\frac{1}{29}-\frac{1}{30}+y:\frac{1}{3}=-4\)
\(\frac{1}{24}-\frac{1}{30}+3y=-4\)
\(\frac{1}{120}+3y=-4\)
\(3y=-4-\frac{1}{120}\)
\(3y=-\frac{481}{120}\)
\(y=-\frac{481}{120}:3\)
\(y=-\frac{481}{360}\)
tìm y :(1/24.25 + 1/25.26 + ... + 1/29.30) . 120 + y : 1/3 = -4
Tìm y: (1/24.25 + 1/25.26 + ...+ 1/29.30 ) x 120 + y: 1/3 = - 4
{1\24.25 + 1\25.26 +...+ 1\29.30} .120+x:1\3 = -4
Tìm y :\(\left(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\right).120+y:\frac{1}{3}=-4\)
Tìm x biết:
(\(\dfrac{1}{24.25}\)+\(\dfrac{1}{25.26}\)+...+\(\dfrac{1}{29.30}\)).120+x:\(\dfrac{1}{3}\)=\(-4\)
Tìm x biết
\(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}+x:\frac{1}{3}=-4\)
bài 2 tìm x biết
4/5 . x = 8/35
3/5 x -1/2 = 1/7
x - 25 %x =0,5
( 1/24.25 + 1/25.26 + ...+1/29.30).120+ x : 1/3 = -4
\(\left(\frac{1}{24.25}+\frac{1}{25.26}+.....+\frac{1}{29.30}\right).120+y:\frac{1}{3}=-4\)
giúp tớ làm phép tính này với:
\(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}\)
trong đó chắc các bạn cũng biết dấu(.) là dấu nhân
