a) `(42-98)-(42-12)-12`
`=42-98-42+12-12`
`=(42-42)+(12-12)-98`
`=-98`
b) `(-5).4.(-2).3.(-25)`
`=(-10).(-100).3`
`=(-1000).3`
`=-3000`.
a,=42-98+(- 42)+12-12 b,=[(- 5).(- 2)].(4.25).3
=10.100.3
=[42+(- 42)]+[12+(- 12)]+-98 =1000.3
=0+0+-98 =3000
=-98
a) (42 - 98) - (42 - 12) - 12 = 42 - 98 - 42 + 12 - 12 = (42 - 42) - 98 + (12 - 12) = -98
b) (-5) . 4 . (-2) . 3 . (-25) = (-5) . (-2) . 4 . (-25) . 3 = 10 . (-100) . 3 = -3000
a) \((42-98)-(42-12)-12 \)
\(=42-98-42-12-12 \)
\( =98\)
b) \((-5).4.(-2).3.(-25) \)
\(=[(-5).(-2)].[4.(-25)].3\)
\(=10.(-100).3\)
\(=-3000\)
a, (42-98)-(42-12)-12
= -56 -(42+12)-12
= -56- 54-12
= -122
b, (-5).4.(-2).3.(-25)
= -20.(-6).(-25)
= -14. (-25)
= 350
Giải:
a) (42-98)-(42-12)-12
=48-98-42+12-12
=(48-48)+(12-12)-98
=0+0-98
=-98
b) (-5).4.(-2).3.(-25)
=(-5.-2.3).(4.-25)
=30.-100
=-3000