Question

BAI 1 viet duoi dang tich cua cac tong sau

1,ab+ac

2, ab- ac +a

3, ax - bx -cx +dx

4,a nhan (b+c ) -d (b +c)

5, ac _ ad + bc - bd

6, ax +by +bx+ay

Answer 1

\(ab+ac=a\left(b+c\right)\)

\(ab-ac+a=a\left(b-c+1\right)\)

\(ax-bx-cx+dx=x\left(a-b-c-d\right)\)

\(a\left(b+c\right)-d\left(b+c\right)=0\Leftrightarrow\left(b+c\right)\left(a-d\right)\)

\(ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(a+b\right)\left(c-d\right)\)

\(ax+by+bx+ay=\left(ax+ay\right)+\left(bx+by\right)=a\left(x+y\right)+b\left(x+y\right)=\left(a+b\right)\left(x+y\right)\)

Answer 2

ab + ac = a( b + c )

ab - ac + a = a( b - c +1 )

ax - bx - cx + dx = x( a - b - c - d )

a( b + c ) - d( b + c ) = 0 <=> ( b + c ) ( a - d )

ac - ad + bc - bd = a( c - d ) + b( c - d ) = ( a + b ) ( c - d )

ax + by + bx + ay = ( ax + ay ) + ( bx + by ) = a( x + y ) + b( x + y ) = ( a + b ) ( x + y )

Answer 3

1, ab + ac = a . ( b + c )

2, ab - ac + a = a . ( b - c + 1)

3, ax - bx - cx + dx = x . ( a - b - c + d )

4, a . ( b + c ) - d . ( b + c) = ( a - d ) . ( b + c )

5, ac - ad + bc - bd = a . ( c - d ) + b . ( c - d ) = ( a + b ) . ( c - d )

6, C1: ax + by + bx + ay = ( ax + ay ) + ( bx + by ) = a . ( x + y ) + b . ( x + y ) = ( a + b ) . ( x + y)

    C2: ax + by + bx + ay = ( ax + bx ) + ( ay + by ) = x . ( a + b ) + y . ( a + b ) = ( x + y ) . (a + b )