Lời giải:
a.
$\frac{7}{23}\times (\frac{-8}{6}-\frac{45}{18})=\frac{7}{23}\times \frac{-23}{6}=\frac{-7}{6}$
b.
$\frac{-5}{9}+\frac{3}{11}+(\frac{-13}{18})\times \frac{3}{11}$
$=\frac{-5}{9}+\frac{3}{11}\times (1-\frac{13}{18})$
$=\frac{-5}{9}+\frac{3}{11}\times \frac{5}{18}$
$=\frac{5}{18}\times (-2+\frac{3}{11})=\frac{5}{18}\times \frac{-19}{11}=\frac{-95}{198}$